Solution: Check the Race Condition

Get a detailed explanation of the solution to the race condition exercise.

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#include <functional>
#include <iostream>
#include <string>
#include <thread>
using namespace std::chrono_literals;
void byCopy(bool b){
std::this_thread::sleep_for(1ms);
std::cout << "byCopy: " << b << '\n';
}
void byReference(bool& b){
std::this_thread::sleep_for(1ms);
std::cout << "byReference: " << b << '\n';
}
void byConstReference(const bool& b){
std::this_thread::sleep_for(1ms);
std::cout << "byConstReference: " << b << '\n';
}
int main(){
std::cout << std::boolalpha << '\n';
bool shared{false};
std::thread t1(byCopy, shared);
std::thread t2(byReference, std::ref(shared));
std::thread t3(byConstReference, std::cref(shared));
shared = true;
t1.join();
t2.join();
t3.join();
std::cout << '\n';
}

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