Task
In this challenge, you had to create a nested function max
which would help its parent function mainMax
to compute the maximum of three numbers.
Solution
A skeleton of the mainMax
function was already provided for you. Let’s look it over.
int mainMax(int a, int b, int c) {
}
mainMax
takes three parameters of type int
and returns a value of type int
.
Let’s go over the step-by-step process for writing the max
function.
max
is intended to break down the bigger problem into a smaller one. WhilemainMax
returns the maximum of three numbers,max
returns the maximum of two of them. This means that it will take two parameters of typeint
and return the greater of the two. To find the maximum of two numbers, a simpleif-else
expression can be used.
int max(int x, int y) {
if(x > y){
return x;
} else{
return y;
}
}
- As for the return value of
mainMax
, we simply needed to call themax
function. The first argument will be one of the three numbers passed tomainMax
and the second argument will be the maximum of the remaining two. To get the second argument, we will use themax
function again as it returns the maximum of two numbers.
return max(a,max(b,c));
You can find the complete solution below:
You were required to write the code given from line 1 to line 10.
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